Optimal. Leaf size=205 \[ \frac{8 i c^2 \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )}{15 a}+\frac{1}{30} a^2 c^2 x^3+\frac{1}{5} c^2 x \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2-\frac{c^2 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)}{10 a}-\frac{4 c^2 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{16 c^2 \log \left (\frac{2}{1+i a x}\right ) \tan ^{-1}(a x)}{15 a}+\frac{11 c^2 x}{30} \]
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Rubi [A] time = 0.138938, antiderivative size = 205, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.368, Rules used = {4880, 4846, 4920, 4854, 2402, 2315, 8} \[ \frac{8 i c^2 \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )}{15 a}+\frac{1}{30} a^2 c^2 x^3+\frac{1}{5} c^2 x \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2-\frac{c^2 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)}{10 a}-\frac{4 c^2 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{16 c^2 \log \left (\frac{2}{1+i a x}\right ) \tan ^{-1}(a x)}{15 a}+\frac{11 c^2 x}{30} \]
Antiderivative was successfully verified.
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Rule 4880
Rule 4846
Rule 4920
Rule 4854
Rule 2402
Rule 2315
Rule 8
Rubi steps
\begin{align*} \int \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^2 \, dx &=-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{1}{10} c \int \left (c+a^2 c x^2\right ) \, dx+\frac{1}{5} (4 c) \int \left (c+a^2 c x^2\right ) \tan ^{-1}(a x)^2 \, dx\\ &=\frac{c^2 x}{10}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{1}{15} \left (4 c^2\right ) \int 1 \, dx+\frac{1}{15} \left (8 c^2\right ) \int \tan ^{-1}(a x)^2 \, dx\\ &=\frac{11 c^2 x}{30}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2-\frac{1}{15} \left (16 a c^2\right ) \int \frac{x \tan ^{-1}(a x)}{1+a^2 x^2} \, dx\\ &=\frac{11 c^2 x}{30}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{1}{15} \left (16 c^2\right ) \int \frac{\tan ^{-1}(a x)}{i-a x} \, dx\\ &=\frac{11 c^2 x}{30}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{16 c^2 \tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{15 a}-\frac{1}{15} \left (16 c^2\right ) \int \frac{\log \left (\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx\\ &=\frac{11 c^2 x}{30}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{16 c^2 \tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{15 a}+\frac{\left (16 i c^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+i a x}\right )}{15 a}\\ &=\frac{11 c^2 x}{30}+\frac{1}{30} a^2 c^2 x^3-\frac{4 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}{15 a}-\frac{c^2 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}{10 a}+\frac{8 i c^2 \tan ^{-1}(a x)^2}{15 a}+\frac{8}{15} c^2 x \tan ^{-1}(a x)^2+\frac{4}{15} c^2 x \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2+\frac{1}{5} c^2 x \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2+\frac{16 c^2 \tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{15 a}+\frac{8 i c^2 \text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{15 a}\\ \end{align*}
Mathematica [A] time = 0.654809, size = 112, normalized size = 0.55 \[ \frac{c^2 \left (-16 i \text{PolyLog}\left (2,-e^{2 i \tan ^{-1}(a x)}\right )+a x \left (a^2 x^2+11\right )+2 \left (3 a^5 x^5+10 a^3 x^3+15 a x-8 i\right ) \tan ^{-1}(a x)^2-\tan ^{-1}(a x) \left (3 a^4 x^4+14 a^2 x^2-32 \log \left (1+e^{2 i \tan ^{-1}(a x)}\right )+11\right )\right )}{30 a} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.085, size = 304, normalized size = 1.5 \begin{align*}{\frac{{a}^{4}{c}^{2} \left ( \arctan \left ( ax \right ) \right ) ^{2}{x}^{5}}{5}}+{\frac{2\,{a}^{2}{c}^{2} \left ( \arctan \left ( ax \right ) \right ) ^{2}{x}^{3}}{3}}+{c}^{2}x \left ( \arctan \left ( ax \right ) \right ) ^{2}-{\frac{{a}^{3}{c}^{2}\arctan \left ( ax \right ){x}^{4}}{10}}-{\frac{7\,a{c}^{2}\arctan \left ( ax \right ){x}^{2}}{15}}-{\frac{8\,{c}^{2}\arctan \left ( ax \right ) \ln \left ({a}^{2}{x}^{2}+1 \right ) }{15\,a}}+{\frac{{a}^{2}{c}^{2}{x}^{3}}{30}}+{\frac{11\,{c}^{2}x}{30}}-{\frac{11\,{c}^{2}\arctan \left ( ax \right ) }{30\,a}}+{\frac{{\frac{4\,i}{15}}{c}^{2}\ln \left ({a}^{2}{x}^{2}+1 \right ) \ln \left ( ax+i \right ) }{a}}+{\frac{{\frac{4\,i}{15}}{c}^{2}\ln \left ( ax-i \right ) \ln \left ( -{\frac{i}{2}} \left ( ax+i \right ) \right ) }{a}}+{\frac{{\frac{4\,i}{15}}{c}^{2}{\it dilog} \left ( -{\frac{i}{2}} \left ( ax+i \right ) \right ) }{a}}-{\frac{{\frac{4\,i}{15}}{c}^{2}{\it dilog} \left ({\frac{i}{2}} \left ( ax-i \right ) \right ) }{a}}-{\frac{{\frac{2\,i}{15}}{c}^{2} \left ( \ln \left ( ax+i \right ) \right ) ^{2}}{a}}+{\frac{{\frac{2\,i}{15}}{c}^{2} \left ( \ln \left ( ax-i \right ) \right ) ^{2}}{a}}-{\frac{{\frac{4\,i}{15}}{c}^{2}\ln \left ( ax+i \right ) \ln \left ({\frac{i}{2}} \left ( ax-i \right ) \right ) }{a}}-{\frac{{\frac{4\,i}{15}}{c}^{2}\ln \left ({a}^{2}{x}^{2}+1 \right ) \ln \left ( ax-i \right ) }{a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} 180 \, a^{6} c^{2} \int \frac{x^{6} \arctan \left (a x\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 15 \, a^{6} c^{2} \int \frac{x^{6} \log \left (a^{2} x^{2} + 1\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 12 \, a^{6} c^{2} \int \frac{x^{6} \log \left (a^{2} x^{2} + 1\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} - 24 \, a^{5} c^{2} \int \frac{x^{5} \arctan \left (a x\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 540 \, a^{4} c^{2} \int \frac{x^{4} \arctan \left (a x\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 45 \, a^{4} c^{2} \int \frac{x^{4} \log \left (a^{2} x^{2} + 1\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 40 \, a^{4} c^{2} \int \frac{x^{4} \log \left (a^{2} x^{2} + 1\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} - 80 \, a^{3} c^{2} \int \frac{x^{3} \arctan \left (a x\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 540 \, a^{2} c^{2} \int \frac{x^{2} \arctan \left (a x\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 45 \, a^{2} c^{2} \int \frac{x^{2} \log \left (a^{2} x^{2} + 1\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + 60 \, a^{2} c^{2} \int \frac{x^{2} \log \left (a^{2} x^{2} + 1\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + \frac{c^{2} \arctan \left (a x\right )^{3}}{4 \, a} - 120 \, a c^{2} \int \frac{x \arctan \left (a x\right )}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} + \frac{1}{60} \,{\left (3 \, a^{4} c^{2} x^{5} + 10 \, a^{2} c^{2} x^{3} + 15 \, c^{2} x\right )} \arctan \left (a x\right )^{2} + 15 \, c^{2} \int \frac{\log \left (a^{2} x^{2} + 1\right )^{2}}{240 \,{\left (a^{2} x^{2} + 1\right )}}\,{d x} - \frac{1}{240} \,{\left (3 \, a^{4} c^{2} x^{5} + 10 \, a^{2} c^{2} x^{3} + 15 \, c^{2} x\right )} \log \left (a^{2} x^{2} + 1\right )^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (a^{4} c^{2} x^{4} + 2 \, a^{2} c^{2} x^{2} + c^{2}\right )} \arctan \left (a x\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} c^{2} \left (\int 2 a^{2} x^{2} \operatorname{atan}^{2}{\left (a x \right )}\, dx + \int a^{4} x^{4} \operatorname{atan}^{2}{\left (a x \right )}\, dx + \int \operatorname{atan}^{2}{\left (a x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a^{2} c x^{2} + c\right )}^{2} \arctan \left (a x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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